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Mathematics 17 Online
OpenStudy (anonymous):

Would the sum of two conservative vector fields on a region be conservative on that region too? Please explain.

terenzreignz (terenzreignz):

Hi, @qwerty54321 What does it mean, for a vector field to be conservative?

OpenStudy (anonymous):

what field of math is this?

terenzreignz (terenzreignz):

Calculus...?

terenzreignz (terenzreignz):

It looks like @qwerty has left this thread. I'll do my best to explain things... feel free to check for errors...

terenzreignz (terenzreignz):

A vector field \(\large \vec R \) is conservative if there exists a function such that \[\huge \nabla f = \vec R \]

terenzreignz (terenzreignz):

Now, suppose we have two vector fields \(\large \vec{R_1}\) and \(\large \vec{R_2}\) Then there exist functions such that \[\huge \nabla f_1 = \vec{R_1}\]\[\huge \nabla f_2=\vec{R_2}\]

terenzreignz (terenzreignz):

Two vector fields which are *conservative* mind...

terenzreignz (terenzreignz):

Then, taking the sum \[\huge \vec R = \vec{R_1}+\vec{R_2}\]

terenzreignz (terenzreignz):

Consider the function \[\huge f = f_1 + f_2\] Then clearly \[\huge \nabla f = \nabla(f_1 + f_2)=\nabla f_1 + \nabla f_2\]

terenzreignz (terenzreignz):

Then \[\huge \nabla f =\vec{R_1}+\vec{R_2}=\vec{R} \] thus proving that the sum of two conservative vector fields is also conservative, as there is a function whose gradient is that sum.

OpenStudy (anonymous):

thank you so much for the explanation; i understand now! :)

terenzreignz (terenzreignz):

No problem.

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