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Physics 13 Online
OpenStudy (yrelhan4):

Electrostatics @Mashy

OpenStudy (yrelhan4):

OpenStudy (anonymous):

you have to calculate the work done in moving the charge from A to the centre.. so we need to find potential difference between the centre of the ring (0 potential) and A.. so basically find potential at A

OpenStudy (yrelhan4):

Umm. Sounds good. I'll try and get back.

OpenStudy (yrelhan4):

390 * 10^9/7 potential at A ? :o

OpenStudy (yrelhan4):

=change in KE?

OpenStudy (yrelhan4):

@Mashy sir?

OpenStudy (anonymous):

wait arr.. ! you got such high potential :O

OpenStudy (anonymous):

OpenStudy (yrelhan4):

Oh right. I dont know what i did. I kinda messed up with the value of charge too. :P

OpenStudy (anonymous):

:P.. check that :P.. m watching dbz and doing it :D..

OpenStudy (yrelhan4):

Check what? Next what? Potential difference=change in KE?

OpenStudy (yrelhan4):

@Mashy ?

OpenStudy (anonymous):

not potential difference.. work done work done = pot diff * charge = change in k.E

OpenStudy (yrelhan4):

oh poop. right. wait a min.

OpenStudy (yrelhan4):

Nope i dont get it. The work done comes out to be 2.82J.. 5-2.82=2.18 ? Not the answer. :/ #mustbeasillymistake

OpenStudy (yrelhan4):

@Mashy

OpenStudy (anonymous):

yea :(.. i figured too.. something is wrong.. check if my potential calcuation is right

OpenStudy (yrelhan4):

Looks good. :(

OpenStudy (anonymous):

lemme think wait!

OpenStudy (anonymous):

m not getting it :-/!?

OpenStudy (yrelhan4):

Nvm. I'll post another question. You have explained a similar question to me before in magnetism. But i would like you to explain it to me again. :P

OpenStudy (yrelhan4):

OpenStudy (anonymous):

find the total charge first!

OpenStudy (yrelhan4):

umm. (Ca^2/4/3 *pi*a^3) ??

OpenStudy (yrelhan4):

No.. integration of Cr^2*4pir^2dr from 0 to a will be the total charge.

OpenStudy (anonymous):

wait arrr

OpenStudy (yrelhan4):

Well that gives me the answer. :D

OpenStudy (anonymous):

show the integration!

OpenStudy (yrelhan4):

integration of Cr^2*4pir^2 dr fro 0 to a --> Ca^5*4pi

OpenStudy (yrelhan4):

Cr^2*4pi*r^2 dr

OpenStudy (anonymous):

ok done :)

OpenStudy (yrelhan4):

Yeah. Thank you.

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