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OpenStudy (yrelhan4):
OpenStudy (anonymous):
you have to calculate the work done in moving the charge from A to the centre..
so we need to find potential difference between the centre of the ring (0 potential) and A.. so basically find potential at A
OpenStudy (yrelhan4):
Umm. Sounds good. I'll try and get back.
OpenStudy (yrelhan4):
390 * 10^9/7 potential at A ? :o
OpenStudy (yrelhan4):
=change in KE?
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OpenStudy (yrelhan4):
@Mashy sir?
OpenStudy (anonymous):
wait arr.. ! you got such high potential :O
OpenStudy (anonymous):
OpenStudy (yrelhan4):
Oh right. I dont know what i did. I kinda messed up with the value of charge too. :P
OpenStudy (anonymous):
:P.. check that :P.. m watching dbz and doing it :D..
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OpenStudy (yrelhan4):
Check what? Next what? Potential difference=change in KE?
OpenStudy (yrelhan4):
@Mashy ?
OpenStudy (anonymous):
not potential difference.. work done
work done = pot diff * charge = change in k.E
OpenStudy (yrelhan4):
oh poop. right. wait a min.
OpenStudy (yrelhan4):
Nope i dont get it. The work done comes out to be 2.82J.. 5-2.82=2.18 ? Not the answer. :/ #mustbeasillymistake
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OpenStudy (yrelhan4):
@Mashy
OpenStudy (anonymous):
yea :(.. i figured too.. something is wrong.. check if my potential calcuation is right
OpenStudy (yrelhan4):
Looks good. :(
OpenStudy (anonymous):
lemme think wait!
OpenStudy (anonymous):
m not getting it :-/!?
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OpenStudy (yrelhan4):
Nvm. I'll post another question. You have explained a similar question to me before in magnetism. But i would like you to explain it to me again. :P
OpenStudy (yrelhan4):
OpenStudy (anonymous):
find the total charge first!
OpenStudy (yrelhan4):
umm. (Ca^2/4/3 *pi*a^3) ??
OpenStudy (yrelhan4):
No.. integration of Cr^2*4pir^2dr from 0 to a will be the total charge.
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OpenStudy (anonymous):
wait arrr
OpenStudy (yrelhan4):
Well that gives me the answer. :D
OpenStudy (anonymous):
show the integration!
OpenStudy (yrelhan4):
integration of Cr^2*4pir^2 dr fro 0 to a --> Ca^5*4pi
OpenStudy (yrelhan4):
Cr^2*4pi*r^2 dr
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