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Where does the graph of y = 2x^2 + x − 15 cross the x-axis?
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@HawkCrimson
any ideas?
no clue
|dw:1365439643199:dw| think of the graph, wat is the y value when any pt is on the x-axis?
0
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yep so when the graph crosses the x-axis the equation is 0 = 2x^2 + x − 15 cause y = 0
ok..
what do i have to do next? @HawkCrimson
solve for x and then state the two points where the curve cuts the x-axis
0 = (x + 3)(2x - 5)
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great so wat r the two coordinates where the graph cuts the x axis?
-3 and 5/2
D
well u didnt give the choice of answers so i cannt confirm it :/ but yea the points r (-3,0) and (5/2, 0)
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