Jacob kicks a soccer ball off the ground and in the air with an initial velocity of 33 feet per second. Using the formula H(t) = −16t2 + vt + s, what is the maximum height the soccer ball reaches?
15.1 feet
16.5 feet
17.0 feet
18.2 feet
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OpenStudy (gabylovesyou):
@HawkCrimson
OpenStudy (anonymous):
brb 1 sec
OpenStudy (gabylovesyou):
okydoky
OpenStudy (gabylovesyou):
@Mertsj
OpenStudy (anonymous):
have you taken calculus?
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OpenStudy (mertsj):
plug in the 33 for velocity and find the vertex. The y coordinate of the vertex is the maximum
OpenStudy (gabylovesyou):
no @ekmath
OpenStudy (anonymous):
then nevermind
OpenStudy (mertsj):
I assume that s is the initial height?
OpenStudy (gabylovesyou):
no clue... ;/
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OpenStudy (mertsj):
Somewhere it tells you what v and s represent. You need to find that.
OpenStudy (gabylovesyou):
give me a sec
OpenStudy (gabylovesyou):
H(t) = objects current height
t = time in air
v = starting upward velocity
s = objects starting height
OpenStudy (mertsj):
So since the object is on the ground, its starting height is 0 and s = 0. So replace v with 33, s with 0 and find the vertex of the parabola.
OpenStudy (gabylovesyou):
ok
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OpenStudy (gabylovesyou):
how do i find the vertex?
OpenStudy (mertsj):
The x coordinate of the vertex is -b/2a. Find it first.
OpenStudy (gabylovesyou):
H(t) = (33 - 16t) t ? thats what u want me to find?