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if a coin is tossed 3 times, what is the probability of setting 3 tails?
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there are 8 possible outcomes, and since 8 is not such a big number we can write them all out
its in a fraction though
(h, h, h) (h, h, t) (h t h) (t, h, h) (h, t, t) (t, h, t) (t. t. h) (t,t,t)
no there are 6 possible outcomes , 2 each time you flip
of those 8 only one has all tails
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answer is therefore \[\frac{1}{8}\]
two possible outcome for each, you do it three times, counting principle gives \(2^3=8\) outcomes, not \(2\times 3=6\)
Nvm satellite73 is completly right, read it wrong sorry!
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