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Divide: 7a + 28/ a-4 divided by a^2 + a -12/ 14a
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\[\frac{(7a+28)(14a)}{(a-4)(a^2+a-12)}\] is a start
then factor and cancel if you can
i need help factoring
\(7a+28=7(a+4)\) for the numerator
\(a^2+a-12=(a+4)(a-3)\) for the denominator
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what would be the next step?
@satellite73
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