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Mathematics 17 Online
OpenStudy (anonymous):

These sequences are all geometric, determine the common ratio. 3, 18, 108, 648, 3888, ... 4, 16, 64, 256, 1024, .... 36, 12, 4, 4/3, 4/9, ... A.) 6 B.) 1/3 C.) 4

jimthompson5910 (jim_thompson5910):

for the first one, pick any term and divide it by the previous term so let's say we pick term 18 (second term) so we would divide it by the previous term (3) to get 18/3 = 6

jimthompson5910 (jim_thompson5910):

this works for any term you pick say you pick 648 (fourth term) and you divide it by 108 (3rd term) 648/108 = 6 etc etc hopefully the idea makes sense

jimthompson5910 (jim_thompson5910):

So in the end, the geometric sequence 3, 18, 108, 648, 3888, ... has the common ratio of 6

OpenStudy (ladiesman217):

6

OpenStudy (anonymous):

thanks so thats means that 4, 16, 64, 256, 1024, would be 4 36, 12, 4, 4/3, 4/9, an 1/3(:

jimthompson5910 (jim_thompson5910):

perfect on both

OpenStudy (ladiesman217):

yes exactly

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