Question

I just need to know if i am right, the answers are in parentheses.

1. Solve for x: (x - 9)^2 = 1 (x=10)
2. Solve for x: x^2 + 24x + 90 = 0 (x=-12\pm3\sqrt{6})
3. Solve for x: 2x^2 - 4x - 14 = 0 (x=1\pm2\sqrt{2})
4. Create your own quadratic equation and demonstrate how it would be solved by graphing, factoring, the quadratic formula, and by completing the square. (My quadratic equation is x^2 - 6x = 0 and x = 0)

Answer 1

1) Is correct

Answer 2

for #1, 10 is just one of the two solutions

Answer 3

there is another you're missing

Answer 4

1 is incomplete

Answer 5

#2 is correct, nice job

Answer 6

1) could also be 8

Answer 7

# 3 is also correct

Answer 8

what about the last one?

Answer 9

x^2 - 6x = 0 has 2 solutions as well

x = 0 is one solution, but there is another

Answer 10

what is the other answer? x = 8 ?

Answer 11

Number 1 can be x=8

Answer 12

x^2 - 6x = 0

has 2 solutions

x = 0 or x = 6

Answer 13

(x - 9)^2 = 1 has the two solutions: x = 10 or x = 8

Answer 14

oh okay(: Thanks a lot! ^-^

Answer 15

np

Answer 16

for the first one this is what i did
(x−9)2=1

((x−9)2−−−−−−−√=1√

x-9=1
x=1+9,x=10
i got the answer since you guys said i got the right answer but did i do the work right?

Answer 17

\[\sqrt{(x-9)^2} = \sqrt1\]

Answer 18

(x-9)^2 = 1

x-9 = plus/minus sqrt(1)

x-9 = sqrt(1) or x-9 = -sqrt(1)

x-9 = 1 or x-9 = -1