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Solve the equation for x: lnx^1/2-2ln3=0
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So far I got ln (x^1/2 / 2.3)=0 I JUST DON'T KNOW HOW TO SOLVE FOR X FROM HERE
\[\ln \frac{x ^\frac{1}{2}}{9}=0\]
\[\ln (x)^{1/2}-2 \ln (3) = 0 \rightarrow \frac{ 1 }{ 2 } \ln (x) - 2 \ln(3) = 0 \rightarrow \ln (x) = 4 \ln (3) \rightarrow \ln(x) = \ln(3)^4\]\[\rightarrow \ln(x) = \ln(81) \implies x = 81\] @aebiri2
\[e^0=\frac{\sqrt{x}}{9}=1\]
Square both sides: \[\frac{x}{81}=1\]
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\[x=81\]
Thanks guys!
I understood both methods
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