Question

what is the point of intersection? 10y=x^2
x^2-6=-2y

Answer 1

I suggest isolating y on both equations.

Answer 2

I would try elimination.

Answer 3

So that you have
\[\huge y=\frac{x^2}{10}\]and\[\huge y=3-\frac{x^2}{2}\]

Answer 4

And make these two functions of x equal to each other, and solve. Good luck :)

Answer 5

thanks guys!

Answer 6

Elimination gives you \[
x^2-6-(x^2)=-2y-(10y) \\
-6=-12y
\]

Answer 7

y=1/2
there is an intersection right?

Answer 8

Try solving this
\[\huge \frac{x^2}{10}=3-\frac{x^2}{2}\]

Answer 9

\[\huge x^2 = 30 - 5x^2\]