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\[\sqrt{5x-1} = \sqrt{4x+9}\] 1/10 1 10 -10
Square both sides... You will get a linear equation...
First square both sides to get rid of the radicals, then get all like terms on one side and others on the other side and solve for x
\[(\sqrt{5x-1})^2=(\sqrt{4x+9})^2\] \[5x-1=4x+9\] You can take it from here right?
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