Question

symplify 6 over the square root of 3 +2

Answer 1

here are the choices
\[\frac{ 4 }{ \sqrt{3} }\]

Answer 2

\[12-6\sqrt{3}\]

Answer 3

\[\sqrt{3}-2\]

Answer 4

and 3

Answer 5

this is what the problem looks like
\[\frac{ 6 }{ \sqrt{3} +2}\]

Answer 6

@Luis_Rivera ?

Answer 7

i think there's a full moon out cause I believe he made a mistake with his denominator..

Answer 8

lol

Answer 9

\[\frac{ 6 }{ \sqrt{3}+2 }*\frac{ \sqrt{3}-2 }{ \sqrt{3}-2 }\]\[\frac{ 6(\sqrt{3}-2) }{ 3-4 }=\frac{ 6(\sqrt{3}-2) }{ -1 }= -6(\sqrt{3}-2) \]

Answer 10

therefore 12 - 6 sqr root 3

Answer 11

which is B