Can someone help me with the attachment below?
the first one is sooooooo easy haha
I got the first one... I think I need help on the rest of them
you just have to write down the 2 linear equations, the first one is... y = 5 and y = x you see the both lines?
y = 6 i mean
I have the first one done..
second one, lets start with the blue line, so to get the y-int, which is "b" in y = mx + b, you count how many steps it went up from 0. as we see it went 2 steps up. so, so far we got y = mx + 2 to find the slope, which is "m" you just do the run over rise. which is 1 so y - x + 2 make sense? if the line is going uphill its positive, if its going downhill its negative
y = x +2 ..typo again
Okay...
do the green one, ok so whats the first step?
So its that the anwer to the blue one?
yea..
But the example is like this....
oh right.. inequalities... mmm what did you say you got for the first one?
\[y \le6\]]
\[y \ge1x\]
ok, so think about it for a sec, why is it y <=6? by looking at the graph
I dont know.. Because i don't know im just super confused on everything
ok so if you look at the blue shaded region, all of it us UNDER 6. that is why Y is less than or equal to 6. because its all under it.
Okay.. So then then the green is all more than 6?
yea, but since they dont shade it with blue, obviously thats not the answer
Okay.. so what does that mean?
pretend you are just doing the line y = mx + b, then do the < > part. if the shaded region is the top/left side, iyts always y =>, and if the shaded region is the bottom or right its always y =<..... and it its a dashed line, you dont use the equal sign just < and >.
THANK YOU!
ok good! lol
Can you just help me with number 5? Because it has a vertical line and Im not really sure what to do with that?
vertical lines are x. so x => 0
thank you
Join our real-time social learning platform and learn together with your friends!