Question

Find the slope of the line tangent to p(x)=(2^x)/(x^2+1) at x=3

Answer 1

\[p(x)=\frac{ 2^x }{ x^2+1}\] is the equation in the problem

Answer 2

i would find dy/dx by using product rule

Answer 3

ok how do you do that

Answer 4

Vdu/dx + Udv/dx looks familiar?

Answer 5

yes but I don't know how to use it

Answer 6

and that is y im here :P

Answer 7

ok

Answer 8

...im not sure how to do it since 2^x is there..

Answer 9

ill have to defrentiate 2^x which im not sure how to do >.>

Answer 10

Well if you don't understand how to do it I can wait for somone else to help me

Answer 11

sry :/ i could of solved it if it was p(x)=( x^2 )/(x^2+1) but i hope someone else helps, if u want i can show u how to use the formula for future reference?