Part 1: Solve the compound inequality 3x + 6 36 and 3x + 6 less than or greater to 54 and show all of your work. You can use

Question

Part 1: Solve the compound inequality 3x + 6 > 36 and 3x + 6 less than or greater to 54 and show all of your work. You can use <= to represent the less than or equal to symbol.
Part 2: Use complete sentences to describe the graph of the solution from Part 1.

anonymous · Answer

@Mertsj @jim_thompson5910 @radar @hartnn

nathan917 · Answer

3x+6>36 3x>30 x>10 AND 3x+6<=54 3x<=48 x<=16 What numbers are greater than 10 and less than or equal to 16?

nathan917 · Answer

Seems like you forgot to say @nathan917

nathan917 · Answer

:P

anonymous · Answer

Hehe sorry. 11,12,13,14, and 15 are the numbers

anonymous · Answer

oh and 16 :P

anonymous · Answer

@nathan917 ?

nathan917 · Answer

Yes. srry was afk for a sec

anonymous · Answer

How do I do part 2.

anonymous · Answer

The graph....x > 10 and x <= 16.
There will be open circle on ten, closed circle on 16, and shading in between the two numbers.

nathan917 · Answer

3x + 6 > 36 subtract 6 from both sides 3x > 30 divide by 3 x > 10 and 3x + 6 =< 54 subtract 6 from both sides 3x =< 48 Divide by 3 x = < 16 So the solution would be greater than 10 but less than or equal to 16.<-- just say a couple things about this.