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\[-2+\frac{ 1 }{ 3 }+\frac{ 3 }{ 2} - \frac{ 2 }{ 3 }^{2} \]
then gives me \[-2+1\frac{ 1 }{ 6 }\]
After this don't know what to do
-2 + 7/6
common denominator and then add
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ok
89/18
@nathan917
whats your question?
after this what do i do next \[-2+1\frac{ 1 }{ 6 }\]
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@nathan917
Im kinda lost on this one ask @Mertsj or @radar
Is it (2/3)^2 or 2^2/3?
no
What do you mean no? It must be one or the other.
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\[-2+\frac{1}{3}+\frac{3}{2}-\frac{4}{3}=-\frac{12}{6}+\frac{2}{6}+\frac{9}{6}-\frac{8}{6}=\]
\[\frac{-20}{6}+\frac{11}{6}=\frac{-9}{6}=\frac{-3}{2}\]
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