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Mathematics 13 Online
OpenStudy (anonymous):

10b^3-40b=0

OpenStudy (anonymous):

Awesome, \(10b^3 - 40b = 0\) is our question, can you think of a common factor to divide by to simplify this equation (hint. it rhymes with hen)

OpenStudy (anonymous):

i think it might be 10?

OpenStudy (anonymous):

Good stuff, so what does dividing everything by 10 give

OpenStudy (anonymous):

b^2-4b

OpenStudy (anonymous):

(I thought originally it was 10b^3??) But if not, that's right. Now we can factorise by b

OpenStudy (anonymous):

oh sorry

OpenStudy (anonymous):

it was

OpenStudy (anonymous):

Ok no worries, so from \(b^3-4b=0\) we can take out a b, because every term in our equation contains a b. So what will you get if you take out a b?

OpenStudy (anonymous):

b(b^2-4)=0?

OpenStudy (anonymous):

Yeah!! And now for the final step of actually finding what b is. Because the original question was a cubic (b^3) we can expect to get 3 answers for b. Can you think of any at the moment?

OpenStudy (anonymous):

im not sure how to find any

OpenStudy (anonymous):

oh wait 0 is one of them

OpenStudy (anonymous):

Ok no problem, let's split our equation up into the different bits. We know that \(b(b^2 - 4) = 0\) Looking at this equation we can split it into the different brackets. Meaning we can write\[b=0\]and \[b^2-4=0\]We are allowed to do this because we know that one or other of these parts must be equal to 0 because anything multiplied by 0 is equal to 0. With me so far?

OpenStudy (anonymous):

im with you

OpenStudy (anonymous):

Fantastic! So we already know that \(b=0\) is one solution. What about the second equation?

OpenStudy (anonymous):

2,-2?

OpenStudy (anonymous):

BOOM!!! Bang on the money! That is correct! So to conclude \(b=0,-2,2\)

OpenStudy (anonymous):

Hope that helped!

OpenStudy (anonymous):

ok sweet thank you! I hope you do this for a living you're really good at it!

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