10b^3-40b=0
Awesome, \(10b^3 - 40b = 0\) is our question, can you think of a common factor to divide by to simplify this equation (hint. it rhymes with hen)
i think it might be 10?
Good stuff, so what does dividing everything by 10 give
b^2-4b
(I thought originally it was 10b^3??) But if not, that's right. Now we can factorise by b
oh sorry
it was
Ok no worries, so from \(b^3-4b=0\) we can take out a b, because every term in our equation contains a b. So what will you get if you take out a b?
b(b^2-4)=0?
Yeah!! And now for the final step of actually finding what b is. Because the original question was a cubic (b^3) we can expect to get 3 answers for b. Can you think of any at the moment?
im not sure how to find any
oh wait 0 is one of them
Ok no problem, let's split our equation up into the different bits. We know that \(b(b^2 - 4) = 0\) Looking at this equation we can split it into the different brackets. Meaning we can write\[b=0\]and \[b^2-4=0\]We are allowed to do this because we know that one or other of these parts must be equal to 0 because anything multiplied by 0 is equal to 0. With me so far?
im with you
Fantastic! So we already know that \(b=0\) is one solution. What about the second equation?
2,-2?
BOOM!!! Bang on the money! That is correct! So to conclude \(b=0,-2,2\)
Hope that helped!
ok sweet thank you! I hope you do this for a living you're really good at it!
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