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Chemistry 11 Online
OpenStudy (anonymous):

the solubility of PBr2 is .021 calculate the Ksp for the reaction

OpenStudy (abb0t):

I think this might require an ICE table. Are you familiar with how to make one of those?

OpenStudy (anonymous):

yes the equation i got was ksp= (.021)(4x^3) does this look right?

OpenStudy (abb0t):

Can you show me your work. I don't fully remember ICE tables 100%. But if you show me your work It can refresh my memoery :)

OpenStudy (vincent-lyon.fr):

Quote :" the equation i got was ksp= (.021)(4x^3) does this look right?" This is wrong. What would x represent, anyway? The answer is much simpler than that. tip: write down the equation of dissolution of \(PbBr_2\) first

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