For each of the following sets of numbers, find the equation of a function that has these numbers as roots. –3 + i and –3 – i
its 1
Find THE Equation. That is a horrible question. 1) There are infinitely many. 2) Are you SURE there are no requirements? Real Coefficients? Anything?
[x-(-3+i)] [x-(-3-i)]=0 (x+3-i)(x+3+i)=0 (x+3)^2 -(i)^2 =0 x2+6x+9+1=0 x2+6x+10+0
the last line should be x2+6x+10=0
That is, indeed, one of the infinitely many possible answers to the question as it is stated.
well anything multiplied with x2+6x+10 is a solution. :)
@tkhunny the requirements are obviously real coefficients and being minimal degree.
No, that is not obvious. There is no such language in the problem statement. If we encourage the student to ignore necessary language, we do a grave disservice. If it is a requirement, it must be stated - hopefully clearly!
@tkhunny I'd agree with you but you're being pedantic. The context gives plenty of clues that this is obviously an elementary algebra or pre-calculus class and thus there is a VERY slim chance they're dealing with coefficients not in \(\mathbb{R}\)! :-) The degree thing I'll give you, though...
There is a very fine line between pedantic and necessary. I don't mind the risk. :-)
@oldrin.bataku BTW - how do you know what category a question is in. I never have that information!
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