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A set of data items is normally distributed with a mean of 60 and a standard deviation of 9. Convert 60 to a z-score. Round your answer to the nearest hundredth as needed.
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\(Z=\frac{X-\mu}\sigma\) The Z-score computes how many standard deviations one is from the mean. Do you recognize that there is *no* difference between the example statistic of \(60\) and the mean for that statistic? This means it is 0 standard deviations away from the mean, i.e. \(Z=0\).
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