Question

\frac { x+1 }{ (x+3)(x-3) } +\frac { 4(x-3) }{ (x-3)(x+3) } +\frac { (x-1)(x-3) }{ (3-x)(x+3) } =

Answer 1

\[\frac{ x+1 }{ (x+3)(x-3) } + \frac{ 4(x-3) }{ (x-3)(x+3) } +\frac{ (x-1) }{ (3-x)(x+3) }\]

Is this right?

Answer 2

that is the equation,yes how ever I am trying to solve it. ^_^

Answer 3

the best thing to do is dothe top first, then work on the bottom. you start with this equation: \[(x+1)+4(x-3)+(x-1)\] how would you solve this?

Answer 4

Ok Well the first two equations have a common denominator so they can be added. So the next step will look like
\[\frac{ (x+1) + 4(x-3) }{ (x-3) (x+3) } + \frac{ (x-1) }{ (3-x) (3+x) }\]
Do you agree??

Answer 5

your right side has a negative implied

Answer 6

3-x = -(x-3)

Answer 7

just move the negative up top, and combine it with the rest