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Mathematics 18 Online
OpenStudy (anonymous):

tan(3x)=sqrt3

OpenStudy (anonymous):

tan(3x) = sqrt(3) tan(3x) = tan(2pi/3) , tan(5pi/3) 3x = 2 pi/3 + pi * k x = pi * (2/9 + k/3) x = 9 * pi * (2 + 3k) this is what i concluded you should confirm it with mertsj or someone else

OpenStudy (anonymous):

@LilySwan you mean \[\Large x=(2+3k){\pi\over9}\]

OpenStudy (anonymous):

@mattlai7 here, \(k=0,\pm1,\pm2,\ldots\) substitute different values for "k" to get solutions in the given domain

OpenStudy (anonymous):

yep i solved it the way i found it easier @electrokid

OpenStudy (anonymous):

meh confused

OpenStudy (anonymous):

ask hartnn

OpenStudy (anonymous):

@hartnn

hartnn (hartnn):

yeah thats correct, which step are you confused on ?

OpenStudy (anonymous):

finding the answer for when x is between 0 and 2pi

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