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Calculus1
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Integrate: xcotx^(2) dx
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\[xcotx^2 dx\]
did you try the substitution x^2 = y ?
like u-substitution?
yeah, so, x^2 =u what's du=.... ?
2x
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more precisely its du = 2x dx right ? so, x dx = (du)/2 put this in your integral, what you get as new integral ?
(1/2u)(cotu)
oh okay so the final answer would be 1/2ln(sinx^(2))+c?
oh, did you mean (1/2)*du*cot u there ? and yes, thats correct.
yeah sorry. i meant that.
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1/2ln(sinx^(2))+c is correct :)
thanks for your help on this!
you are most welcome ^_^
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