Five marbles are randomly selected with replacement. The probability of a black marble being chosen is 15%. What is the probability that at least 2 marbles are black?
Let X be the number of black marbles drawn, then X ~ Bin(5,0.15). Now calculate P(X>=2).
(x>=2) or (x=2) ?
Well, it's more convenient to calculate the complement probability first, that is P(X<=1)
so, if I find the compliment, it would be (5c1) * (.15)^1 * (.85)^4 + (5c2) * (.15)^2 * (.85)^3 ? ? ?
No, P(X<=1) = P(X=0) + P(X=1)
You should read '<=' as 'less than or equal to'
Right.
"No, P(X<=1) = P(X=0) + P(X=1)" I don't have any idea where to go from here.
Calculate P(X=0), and then P(X=1) , and then add them up to find the complement probability.
hmm
Well, you know the formula right? P(X=k) = nCk*p^k*(1-p)^(n-k), just plug the numbers in
yeah, just having a hard time attributing the variables. Would "n" be 5?
Aw well... - Don't feel obliged to continue to put up with me any longer. I'll stay with my professor tomorrow. Thank you for your patience and help.
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