Each exterior angle of a regular polygon is approximately 51.43. How many sides does the polygon have?
i think it is S= (n-2)180
remember you are looking for the number of sides.
for "N" sided polygon, there are "N" number of exterior angles. sum of all exterior angles should be 360
to find 1 angle of a regular convex polygon of n sides = 360/n
so, the general formula for exterior angle for "N" sides would be, \[\theta={360^\circ\over N}\]
\[51.43=\frac{ 360 }{ n}\]
yes!
now do the rest
this is true for a "Regular convex polygon" only
n should equal the amount of sides a polygon has right???
yep. and that is what you are finding here..
how many sides did you find out?
im strying to figure it out
\[51.43={360\over n}\\ n\times51.43=\cancel{n}\times{360\over \cancel{n}} \]
similarly, divide both sides by "51.43"
so i divide 360 by 51.43???
yes
ok i got 6.99 is that correct ???
now, can you have 6.99 number of sides? NO so, round it to the nearest integer. that means, you have "7" sides to the polygon
ohh ok i was going to do that thank you :D
good. yw
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