Question

Find the perimeter of ABC. Round your answer to the nearest tenth.

A (-4,-1) B (4,5) C (4,-2)

The distance formula is (x2-x1)^2 + (y2-y1)^2

Answer 1

it's actually

d = sqrt( (x2-x1)^2 + (y2-y1)^2 )

but you are close

Answer 2

you use that formula to find the lengths of

AB
AC
BC

then add up these lengths

Answer 3

i'm still confused about how to do it, but thanks

Answer 4

I'll show you how to find the distance from A to B to get the length AB

Answer 5

A perimiter is the distance of all three sides. The points you have ben given are where the sides meet.

Answer 6

A = (-4,-1) B = (4,5)


(x1,y1) = (-4, -1) ----> x1 = -4, y1 = -1


(x2,y2) = (4, 5) ----> x2 = 4, y2 = 5


-------------------------------------------------------


d = sqrt((x2-x1)^2+(y2-y1)^2)


d = sqrt((4-(-4))^2+(5-(-1))^2)


d = sqrt((4+4)^2+(5+1)^2)


d = sqrt((8)^2+(6)^2)


d = sqrt(64+36)


d = sqrt(100)


d = 10


So exact distance between the two points, A and B, is 10 units.


So AB is 10 units long

Answer 7

do the same for AC and BC

then add up the 3 sides

Answer 8

Does that help?