Question

Find the maximum y-value on the graph of y=f(x).

f(x)= -x^2+4x+3

Answer 1

maxiumum y value is
(-b^2 + 4ac )/ 4a

Answer 2

So a=-1, b=4, c=3?

Answer 3

yes

Answer 4

so the answer is -1

Answer 5

@MixMasterTX there is some mistake. check it out again.

\(\cfrac{-(4)^2 + 4(-1)(3)}{4(-1)}\)

Answer 6

@mathslover Good job, buddy

Answer 7

Thank you mertsj . Let us see what MixMasterTX tells the answer , @MixMasterTX can you tell us what is the answer?

Answer 8

@ Mathslover Congratulations on becoming 99!!

Answer 9

Thank you Mertsj again :) ;)

Answer 10

16+(-12)/-4

Answer 11

4/-4 = -1

Answer 12

-4^2 = -16

Answer 13

-(4^2) = -16

Answer 14

@MixMasterTX check the minus there :

\(\cfrac{\color{blue}{{-}} (4^2) -12}{-4}\)

Answer 15

yes. mathslover is correct!!

Answer 16

OK...so what I was doing was squaring -4 and not 4 with the negative sign.

Answer 17

-(4)^2 is -16 but (-4)^2 is 16
You must carefully note the difference.

Answer 18

-16-12/-4
-28/-4
Answer is 7

Answer 19

yes it is.

Answer 20

Yep!

Answer 21

Good work MixMasterTX.

Answer 22

Thanks mathslover and mertsj!!

Answer 23

Thanks to Taylor also.

Answer 24

You are correct!!