Write a proof sequence for the following assertion. Justify one of the steps in your proof using the result of Example 1.8. not(a and notb) notb implies nota
I think you will need one of De Morgan's Laws to do this. De Morgan's laws (Philosophy / Logic) (in formal logic and set theory) the principles that conjunction and disjunction, or union and intersection, are dual. **Thus the negation of P & Q is equivalent to not-P or not-Q** [named after Augustus De Morgan (1806-71), British mathematician] http://tinyurl.com/cvpt2mm
For your posted first expression: not(a and notb) Write it symbolically as ~(a ^ ~b) --> The character ^ means "and." Then, given: notb which is ~b in symbolic form. Show: nota which is ~a in symbolic form.
The task is to show that ~(a ^ ~b) implies ~a if given ~b. ------------------------------------ ~(a ^ ~b) ==> ~a V ~(~b) ==> ~a V b. ~a V b ~b _______ Therefore, ? @malia667
Yes that sounds right. thanks!
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