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Chemistry 15 Online
OpenStudy (anonymous):

Calculate the heat required to melt 25.7 grams of ice. Do i use Q=MCAT? Or what...

OpenStudy (mos1635):

melt ...water??

OpenStudy (anonymous):

My paper said water.... I guess it's ice @mos1635

OpenStudy (mos1635):

ok ice at what temp ??

OpenStudy (anonymous):

That isn't given either....

OpenStudy (mos1635):

ok lets take the general case: Q(total)= Q(from -θ to 0 degrees) + Q(from 0deg ice to 0deg liquid) Q(tot)=m*c*Δθ + λ*m....

OpenStudy (anonymous):

Q= 25.7(333)

OpenStudy (anonymous):

@mos1635

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