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Calculate the heat required to melt 25.7 grams of ice. Do i use Q=MCAT? Or what...
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melt ...water??
My paper said water.... I guess it's ice @mos1635
ok ice at what temp ??
That isn't given either....
ok lets take the general case: Q(total)= Q(from -θ to 0 degrees) + Q(from 0deg ice to 0deg liquid) Q(tot)=m*c*Δθ + λ*m....
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Q= 25.7(333)
@mos1635
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