Find the area between the the curves

r^2=sin2theta
r^2=cos2theta

I get that they intersect at pi/8 and once again in the 3rd quadrant. by symmetry I should take the integral and multiply by 2 of:

1/2 sin2theta from 0 to pi/8 + 1/2 cos2theta from pi/8 to pi/2.

Where am I going wrong. HELP!

Question

Find the area between the the curves

r^2=sin2theta
r^2=cos2theta

I get that they intersect at pi/8 and once again in the 3rd quadrant. by symmetry I should take the integral and multiply by 2 of:

1/2 sin2theta from 0 to pi/8 + 1/2 cos2theta from pi/8 to pi/2.

Where am I going wrong. HELP!

anonymous · Answer

I get the answer 1/2+(sqrt of 2)/4 BUT the book's answer is 1-(sqrt 2)/2