Question

can someone check these please?

Answer 1

it wolnt let me see the attachments

Answer 2

it's a word document

Answer 3

can you type it

Answer 4

and can you help me it's history can you

Answer 5

I am checking it. Just wait..

Answer 6

i dont know what that is sorry

Answer 7

First three are right.

Check for fourth one again...

Answer 8

Working on fifth and sixth..

Answer 9

can you show me how to do 4?

Answer 10

It looks good to me. I just learned how to do these too.

Answer 11

do you do flvs? have you turned in this assignment already? @fourme

Answer 12

i spent all day on this assignment :/

Answer 13

@waterineyes are 5 and 6 correct? :/

Answer 14

what about just (35z-2xy^2)/(28x^2 yz) or 4?

Answer 15

for 4*

Answer 16

4th and 6th are wrong..

Answer 17

How you got y^2 there??

Answer 18

Do you still need help?

Answer 19

UM

Answer 20

What I got is:
\[\implies \color{green}{\frac{35z - 2xy}{28x^2yz}}\]

Answer 21

6th one is easy but you have taken it somewhere else..

Answer 22

i redid it and got [3(x+5)]/(x^3+ 14x^2+ 63x+90) for 6

Answer 23

\[\frac{2}{(x+3)(x+5)} + \frac{1}{(x+5)(x+6)} \implies \frac{2(x + 6) + 1(x + 3)}{(x+3)(x+5)(x+6)}\]

Just solve this..

Answer 24

(x+5) and (x+5) will get cancelled why are you multiplying (x + 5) in the denominator??

Answer 25

Do not touch the denominator, keep it in factors only..

Answer 26

i'm so confused ._.

Answer 27

Where tell me??

Answer 28

Simply from how you got this in the denominator??

x^3+ 14x^2+ 63x+90

Answer 29

I mean just factorize it..

Answer 30

(x+3)(x+5)(x+6) = x^3+ 14x^2+ 63x+90 Right??

Answer 31

i think so

Answer 32

You must think so..

So keep it in factors form, don't multiply them..

Answer 33

So you will get:
\[\frac{3(x + 5)}{(x+3)(x+5)(x+6)}\]

Here cancel (x+5)..

Answer 34

Not getting??

Answer 35

no, i'm not getting it :/

Answer 36

Can you tell me where are you not getting??

Answer 37

Let us start from the start..

\[\frac{2}{(x+3)(x+5)} + \frac{1}{(x+5)(x+6)} \implies \frac{2(x + 6) + 1(x + 3)}{(x+3)(x+5)(x+6)}\]

Getting this much??

Answer 38

Or in your language:
\[\frac{2}{(x+3)(x+5)} + \frac{1}{(x+5)(x+6)} \implies \frac{2}{(x + 3)(x+5)} \times \frac{x+6}{x+6} + \frac{1}{(x+5)(x+6)} \times \frac{x + 3}{x + 3}\]

Answer 39

\[\frac{2}{(x+3)(x+5)} + \frac{1}{(x+5)(x+6)} \]
\[\implies \frac{2}{(x + 3)(x+5)} \times \frac{x+6}{x+6} + \frac{1}{(x+5)(x+6)} \times \frac{x + 3}{x + 3}\]

Now getting or not??

Answer 40

Here you can see that the denominators are equal now.. So just combine numerators part..

Answer 41

@AriPotta reply where are you not getting??

Answer 42

3/[(x+6)(x+3)] ?

Answer 43

Deleted??

Answer 44

Yep that one is right..

Answer 45

finally lol. thanks so much

Answer 46

So we are done with 5, 1,2, 3,4, 6..

Answer 47

I am not sure about 5th one but I got different answer than you..

Can you check once again for your 5th part??