Question

sin(A+B) and sin(A-B)
A=180 B=60
please help!

Answer 1

I know the formulas, but don't know how to show the work or anything. pretty confusing.

Answer 2

hey, A =180, B = 60 you don't know how many A - B is?

Answer 3

I have to find those like first find sin(A+B)
AND THEN sin (A-B)

Answer 4

no need to put formula here, just A+ B and then A- B , take sin of the sum, or of the different

Answer 5

the formula to solve those are sin(A+b)= sinAcosB+cosAsinB

Answer 6

I know, but in case A, B are not special like that.

Answer 7

but if you still want to take this, you know the formula, just plug them in the formula

Answer 8

I have to find the exact value the only thing that throws me off is the 180

Answer 9

ok, first, let my method gives you the right answer A + B = 240 , sin 240 =?

Answer 10

yes

Answer 11

now, your method, sin (A + B) = sinA cos B + sinB cos A
yours is sin (180 + 60) = sin (180) cos (60) + sin (60) cos (180)
sin 180 = 0 so, the first term =0 you just have sin (60) cos (180)
sin (60)= sqr (3)/2.
cos (180) =-1
so, sin (60) * c0s(180) = sqr (3)/2 ( -1 ) = - sqr (3) /2
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Answer 12

your'e the best!!!!!

Answer 13

do the same with part B)

Answer 14

I am gonna delete every thing, you are better do the stuff by yourself

Answer 15

thanks for the help though.

Answer 16

ok. but to me, just add A +B or A -B . A-B = 120, sin (120) = ???? quite easier than apply formula

Answer 17

I have one question since my teacher never really teached us this how would you find the exact value of sin120?

Answer 18

wait, I show you the link

Answer 19

look up the values as you wish

Answer 20

ooohh the circle !

Answer 21

hehehe... did your prof show you that circle? I think he did

Answer 22

Yes he did but very vaguely! but thank's to you you have brought back my memory :)

Answer 23

OK ,