Question

i need some math help

Answer 1

You need a common denminator. That means multiplying the bottom parts so that they match. Hwever, if you multiply the bottom of a fraction, you must multiply the top by the same thing.

Do you know hoe to do that or do you need an example?

Answer 2

example pls

Answer 3

The basic example is:
\[\frac{1}{2}-\frac{1}{3}\Rightarrow \frac{1\times 3}{2\times 3}-\frac{1\times 2}{3\times 2}\Rightarrow \frac{3}{6}-\frac{2}{6}\Rightarrow \frac{3-2}{6}= \frac{1}{6}\]

Now, in your case you have \((x-3)\) and \((x-2)\) on the bottom. Those are what determine how you need to multiply.

Answer 4

So, do you see what needs to be multiplied by what, or are you still lost?

Answer 5

well i get that but the only thing i can choose is this

Answer 6

Once you start with these, there is usually simolification and ther things that happen. So getting the first step right is very important.

Answer 7

That is fine. Those are simplified choices. If you look at what I did with basic fractions and apply it here, the first step is this:
\[\frac{3}{x-3}\cdot \frac{x-2}{x-2} - \frac{5}{x-2}\cdot \frac{x-3}{x-3}\]So what happens when you multiply those out? They left the bottom with it as \((x-3)(x-2)\) so there is not much work to do there. The top you need to actually multiply, then subtract the entire right part from the left part.

Answer 8

thank you soooooo much!!!!

Answer 9

So, do you see how to do this?

Answer 10

ya

Answer 11

Just be careful with the subtraction part. That negative goes trough the entire right top! That will change the signs.

Answer 12

ok :)

Answer 13

And if you have a guess, I can tell you if it is right.

Answer 14

thanks but i got it and thank you for the help

Answer 15

np. Have fun!