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Algebra 16 Online
OpenStudy (anonymous):

x,y and z are positive integers such that x

OpenStudy (anonymous):

Try to break this question down. To find the maximum value of x+y+z. We know that z is dependent on x. The bigger x is, the bigger z is. We also know that y is bigger than x. From this we can deduce that finding max value of x will solve our problem! x+y = 201. x<y max value for x is 100, meaning that y is 101. and z is 300

OpenStudy (anonymous):

Therefore x+y+z =501

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