Question

Can someone please help me with this problem?

How does aluminum bromide react with barium hydroxide?

Here's the chemical equation:
AlBr3(aq) + Ba(OH)2(aq) -->

Answer 1

Separete them by charge and then combine positive with negative. Finally, check to make sure they are balanced!

It might help to make a list of how many of each atom you have on the reactants side, and product side. Remember that you need to have equal amounts on both sides. Atom's don't just disappear. Try it out. If you stll need help, ask questions! It's the best way to learn by asking questions.

Answer 2

Thank you for the hint, but I am still quite confused. The charge for aluminum is 3-, and the charge for bromine/bromide is +, and that makes sense. However, the other reactant, barium, which has a charge of 2-, and the poly-atomic ion, hydroxide, which has a charge -, can't go together. Is that what I am supposed to separate?

Answer 3

I meant to say that barium has a charge of 2+, and so the positive and negative are already together. Is this an impossible equation?

Answer 4

CAN YOU PLEASE HELP ME

Answer 5

No. That's correct. Just put the + with the - of the other compound.

For instance, you start with: \(Al(OH)_3\) + _________
NOW
notice how you have THREE hydroxide ions \((OH^-)\) ions on the product side and TWO on the reactant side.... So this is where I was talking about balancing. Remember, what you do to one side, you also do to the other.
If you add a 2 to the product side, you must also add 2 to the reactant side.
ALSO one last thing to know is that it follows the distributive property!
If you have \(2Al(OH)_3\) it means you have TWO alumnium atoms now and SIX hydroxide ions. Can you try it now?