Find an integer, x, such that 5, 10, and x represent the lengths of the sides of an obtuse triangle. A. 4 B. 5 C. 6 D. 11
does your problem specify which will be which side?
Use this theorem: If a, b, and c represent the lengths of the sides of a triangle, and c is the longest length, then the triangle is obtuse if c^2 > a^2 + b^2.
well the only way that could possibly work out, or at least as far as i can tell, is that 10 is the longest side, which would mean that alll a, b,and c would work
@dave0116 @MLeighW Here's why I think option A of 4 will not work. That would give the sides as 4, 5, and 10. Recall the Triangle Inequality Theorem which states that one side of a triangle is shorter than the sum of the lengths of the other two sides. 10 is not less than (4+5). No triangle with sides 4, 5, and 10 exists.
haha well it seems that you know more about this than me, i am only recalling my knowledge of triangles, i will bow out now since i am obviously of no help hahaha
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