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Mathematics 17 Online
OpenStudy (anonymous):

If the cost of manufacturing x items is c(x) = x^3 + 20x^2 + 90x + 15 , find the marginal cost function and compare the marginal cost at x = 50 and the actual cost of manufacturing the 50th item.

OpenStudy (anonymous):

@amistre64 can u help?

OpenStudy (amistre64):

the word marginal should give you the idea of a derivative

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

so how would i do that will it be likfe this c'(50) = x^3 + 20x^2 + 90x + 15 or?

OpenStudy (amistre64):

yes, but youd actually need to take the derivative of the right hand side ....

OpenStudy (anonymous):

so the derivative of x^3 + 20x^2 + 90x + 15?

OpenStudy (amistre64):

yes, find the derivative of: x^3 + 20x^2 + 90x + 15, which will then be your marginal cost function i recall a question similar to this awhile back that needed to be divided by x; not too sure if we need that here tho

OpenStudy (anonymous):

ok i got 3x^2 + 40x + 90

OpenStudy (amistre64):

that is a good marginal cost function; and since there is no word "average" being tossed about the divide by x is not an issue http://homepage.smc.edu/wong_betty/math28/pdf%20files/C11%20SSM%20Ch%203%20pt%205.pdf

OpenStudy (anonymous):

ok

OpenStudy (amistre64):

C(50) - C(49) should be the exact cost whereas C'(50) is the marginal cost value

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

so i substitute those into the derivative or ??

OpenStudy (amistre64):

you have a cost function C(x); find: C(50) - C(49) you have a marginal cost function as C'(x), find: C'(50) and compare the values

OpenStudy (anonymous):

so i do that with x^3 + 20x^2 + 90x + 15 or 3x^2 + 40x + 90

OpenStudy (amistre64):

what is your C(x) function?

OpenStudy (anonymous):

x^3 + 20x^2 + 90x + 15

OpenStudy (amistre64):

and when x=50, what value does that produce?

OpenStudy (anonymous):

ok i got 1125015

OpenStudy (amistre64):

now, what is the value when x=49?

OpenStudy (anonymous):

i got 1082474

OpenStudy (amistre64):

good, now subtract the value for 50, from the value for 49; what do we end up with?

OpenStudy (anonymous):

i get 42541

OpenStudy (amistre64):

1125015 -1082474 ---------- 42541 is what i get too

OpenStudy (amistre64):

now, what is our C"(x) function?

OpenStudy (amistre64):

err, C'(x) function that is

OpenStudy (anonymous):

its 3x^2 + 40x + 90

OpenStudy (amistre64):

and what value do we get for that function when x=50?

OpenStudy (anonymous):

i get 24590

OpenStudy (amistre64):

now it asks you to compare the results actual cost is: 42541 marginal cost is: 24590 what it means by compare, i havent a clue

OpenStudy (anonymous):

well the actual cost is bigger? i don't know.. :/

OpenStudy (amistre64):

lol, that would seem fine to me, but im not the one grading it so i cant really say what it means to compare them for ...

OpenStudy (anonymous):

okay thanks for the help

OpenStudy (amistre64):

good luck :)

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