If the cost of manufacturing x items is c(x) = x^3 + 20x^2 + 90x + 15 , find the marginal cost function and compare the marginal cost at x = 50 and the actual cost of manufacturing the 50th item.
@amistre64 can u help?
the word marginal should give you the idea of a derivative
okay
so how would i do that will it be likfe this c'(50) = x^3 + 20x^2 + 90x + 15 or?
yes, but youd actually need to take the derivative of the right hand side ....
so the derivative of x^3 + 20x^2 + 90x + 15?
yes, find the derivative of: x^3 + 20x^2 + 90x + 15, which will then be your marginal cost function i recall a question similar to this awhile back that needed to be divided by x; not too sure if we need that here tho
ok i got 3x^2 + 40x + 90
that is a good marginal cost function; and since there is no word "average" being tossed about the divide by x is not an issue http://homepage.smc.edu/wong_betty/math28/pdf%20files/C11%20SSM%20Ch%203%20pt%205.pdf
ok
C(50) - C(49) should be the exact cost whereas C'(50) is the marginal cost value
okay
so i substitute those into the derivative or ??
you have a cost function C(x); find: C(50) - C(49) you have a marginal cost function as C'(x), find: C'(50) and compare the values
so i do that with x^3 + 20x^2 + 90x + 15 or 3x^2 + 40x + 90
what is your C(x) function?
x^3 + 20x^2 + 90x + 15
and when x=50, what value does that produce?
ok i got 1125015
now, what is the value when x=49?
i got 1082474
good, now subtract the value for 50, from the value for 49; what do we end up with?
i get 42541
1125015 -1082474 ---------- 42541 is what i get too
now, what is our C"(x) function?
err, C'(x) function that is
its 3x^2 + 40x + 90
and what value do we get for that function when x=50?
i get 24590
now it asks you to compare the results actual cost is: 42541 marginal cost is: 24590 what it means by compare, i havent a clue
well the actual cost is bigger? i don't know.. :/
lol, that would seem fine to me, but im not the one grading it so i cant really say what it means to compare them for ...
okay thanks for the help
good luck :)
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