Find the production level that minimizes the average cost. c(x) = 0.1x^2 + 3x + 2000
draw the graph and find the lowest value for c
how do i do that?
or just derivate the equation and solve for it = 0
okay
I got x = -15 @Diogo
Now put that value on the first equation to find C(-15)
ok 0.1(-15)^2 + 3(-15) + 2000 ?
i got 1977.5
so what do i do next?
@Mertsj can u help?
\[c'(x)=.2x+3=0 ` ` if ` ` x = -15\] \[.1(-15)^2+3(-15)+2000=1977.50=\]= production level at which cost is minimum.
ok
so thats it?
yes. You you derivate and igualate the derivate of that function to 0 and calculate the root that will give you the minimum value. So all you need now is to insert it on the main equation and find the key number :)
I havent really solve your problem so i don't have a value to give you in order to compare with your answer. But if you used all the tips i gave that should be correct
how?
ohh ok so i'm done
Ok. I researched this. No you are not done.
ohh ok
what do i do next?
Back to the beginning. To find the cost of 1 item, we need to divide the original function by x.
ok so 0.1x^2 + 3x + 2000/(x)
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