Find the production level that minimizes the average cost. c(x) = 0.1x^2 + 3x + 2000
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
draw the graph and find the lowest value for c
OpenStudy (anonymous):
how do i do that?
OpenStudy (anonymous):
or just derivate the equation and solve for it = 0
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
I got x = -15 @Diogo
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Now put that value on the first equation to find C(-15)
OpenStudy (anonymous):
ok 0.1(-15)^2 + 3(-15) + 2000 ?
OpenStudy (anonymous):
i got 1977.5
OpenStudy (anonymous):
so what do i do next?
OpenStudy (anonymous):
@Mertsj can u help?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mertsj):
\[c'(x)=.2x+3=0 ` ` if ` ` x = -15\]
\[.1(-15)^2+3(-15)+2000=1977.50=\]=
production level at which cost is minimum.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so thats it?
OpenStudy (anonymous):
yes.
You you derivate and igualate the derivate of that function to 0 and calculate the root that will give you the minimum value.
So all you need now is to insert it on the main equation and find the key number :)
OpenStudy (anonymous):
I havent really solve your problem so i don't have a value to give you in order to compare with your answer. But if you used all the tips i gave that should be correct
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
how?
OpenStudy (anonymous):
ohh ok so i'm done
OpenStudy (mertsj):
Ok. I researched this. No you are not done.
OpenStudy (anonymous):
ohh ok
OpenStudy (anonymous):
what do i do next?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mertsj):
Back to the beginning. To find the cost of 1 item, we need to divide the original function by x.