Question

g(x) = √5x - 4
h(x) = 4x2 + 7
Find: h(g(1))

Answer 1

is the g(x) \[\sqrt{5x-4} or \sqrt{5}x-4\]

Answer 2

So let's assume you have g(x) = \[\sqrt{5x-4}\]
let's find g(1) = \[\sqrt{5*1-4}\] = \[\sqrt{1}\] = 1
g(1) = 1

so, h(1) = 4*1*2+7 = 56

you have mistakes in your question by the way, what do you mean by 4x2? I solved it as if you had something like 8x+7