Question

what does d=1/2at2+ViT mean?

Answer 1

\[distance =\frac{ acceleration \times time ^{2} }{ 2 } +initialvelocity \times time\]

Answer 2

\[\LARGE D=ut+\frac{1}{2}at^{2}\]
Or
\[\LARGE D=V_i t+\frac{1}{2}at^2\]
Vi=initial velocity
a=acceleration
t=time
It is one of the Newton's Equation's for uniform motion.