Mathematics
8 Online
OpenStudy (anonymous):
√5x-1 = √4x+ 9 solve the equation
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OpenStudy (anonymous):
X=10?
OpenStudy (anonymous):
thank you so much could you help with one more
OpenStudy (anonymous):
was that a guess or did you figure it out
OpenStudy (anonymous):
√5x-1 = √4x+ 9 => 5x-1=4x+9
OpenStudy (anonymous):
ok i see wht you are doing? How about this one 2√6 + 3√96
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OpenStudy (anonymous):
-1 and 9 under the √??
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
if not then (√5-√4)*√x=9
√x=9/(√5-√4)=9(√5+√4)
OpenStudy (anonymous):
they are under the √
OpenStudy (anonymous):
could you help me with the other one
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OpenStudy (anonymous):
of course wut is it
OpenStudy (anonymous):
2√6 + 3√96
OpenStudy (anonymous):
2√6 + 3√96=2√6+3*4*√6=14√6
OpenStudy (anonymous):
ty so much if your up to it i have a few more
OpenStudy (anonymous):
ok is it assignments at school?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
(8+√11) (8-√11)
OpenStudy (anonymous):
4=√p-2
OpenStudy (anonymous):
(8+√11) (8-√11)=8^2-11=5
4=√p-2 =>16=p-2 p=18
OpenStudy (anonymous):
ok that one might not be right because its not a option
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OpenStudy (anonymous):
which one?
OpenStudy (anonymous):
both
OpenStudy (anonymous):
sorry made a mistake...8^2-11=53
OpenStudy (anonymous):
ok that one is there :-)
OpenStudy (anonymous):
but I dont know whats wrong with the next one
what are those options?
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OpenStudy (anonymous):
√6, 36, 3, 6
OpenStudy (anonymous):
i have 2 more if you dont mind i will leave you a medal
OpenStudy (anonymous):
if -2 is under √ then 36 is correct
OpenStudy (anonymous):
bring them on!...
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
lol √3 + 4√3
OpenStudy (anonymous):
what is the domain of the function? y=√3x+3
OpenStudy (anonymous):
5√3
x->0 since the number under √ has to be higher than or equal to 0
OpenStudy (anonymous):
which one is that??
OpenStudy (anonymous):
√3 + 4√3=5√3
the domain x->0
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OpenStudy (anonymous):
for that one i just need the equation figured out
OpenStudy (anonymous):
the domain one is y=√3x+3
OpenStudy (anonymous):
thank you for your smarts!! How do i give u a medal??
OpenStudy (anonymous):
thats enough?
OpenStudy (anonymous):
just click best response tk:D
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OpenStudy (anonymous):
i still need the domain one if you can
OpenStudy (anonymous):
what is the domain of the function y=√3x+3
OpenStudy (anonymous):
for y=√(3x+3) the domain is x->-3
i dont know whats wrong with the previous answer
OpenStudy (anonymous):
the options are x< -1, x>1, x>-1
OpenStudy (anonymous):
x>-1 then though i think x=-1 is also acceptable
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OpenStudy (anonymous):
ok thank you I gave you a medal, you really helped me out
OpenStudy (anonymous):
glad :D