Use graphical approximation techniques or an equation solver to approximate the desired interest rate. A person makes annual payments of $1000 into an ordinary annuity. At the end of 5 years, the amount in the annuity is 5767.98. What annual nominal compounding rate has this annuity earned? Rate needs to be rounded 2 decimal places.
\[x^5 = 767.98\]
the present value of an annuity should be 0; also refered to as an internal rate of return i think
1000/(1+r)^1 1000/(1+r)^2 1000/(1+r)^3 1000/(1+r)^4 1000/(1+r)^5 ------------- sum = 5767.98
lol, almost had that right ....
sum would have to be zero for net present value :) best thing to do according to my accounting classes was to guess at it
\[FV=PV\frac{1-(1+r)^n}{r}\] \[5767.98=1000\frac{1-(1+r)^5}{r}\] \[5.76798=\frac{1-(1+r)^5}{r}\] \[5.76798r=1-(1+r)^5\] see where the 2 graphs intersect
forgot a negative but i get about 7.15% http://www.wolframalpha.com/input/?i=y%3D-5.76798x%2C+y%3D1%E2%88%92%281%2Bx%29%5E5 http://www.wolframalpha.com/input/?i=-1000%281-%281.0715%29%5E5%29%2F%28.0715%29
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