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Let u = <3, -1>, v = <-6, -6>. Find 9u + 2v.
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Can you first find \(9\bf \vec u \)?
@ParthKohli would it be 9(3+-6)=-27?
if so 2v =-14?
Erm, well no...
dont add them together, leave it in the form of a vector
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\[9{\bf \vec u} = 9 \times \langle 3,-1) = \langle 9\times 3, 9 \times -1\rangle = \langle 27,-9\rangle \]
Can you do it for \(2\bf \vec v\)? We'll add them together afterwards.
2v= 2(-6,-6)= (2x-6, 2 x -6)= (-12,-12)
Nailed it! Now add them.
15,-21
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Whoa, that's correct :-D
Thanks for your help
No problem!
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