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Chemistry 14 Online
OpenStudy (anonymous):

Balanced equation for the neutralization of these 2 HCl , Ca(OH)2

OpenStudy (anonymous):

let's assume that HCl dissociates completely, because it's a strong acid. the complete ionic equation: 2H^+(aq) + 2Cl^-(aq) + Ca(OH)2(s) -> 2H2O(l) + Ca^2+(aq) + 2Cl^-(aq)

OpenStudy (anonymous):

o so is it the same as Ca(OH)2(s) + 2HCl(aq) --> 2H2O +CaCl2 (aq) the answer is this i just don know how the book gets it

OpenStudy (anonymous):

@iforgot the book's version is the molecular equation (according to chemistry: the central science). it's the same.

OpenStudy (anonymous):

o okies tyvm

OpenStudy (anonymous):

here is the net ionic equation, again according to the textbook: 2H^+(aq) + Ca(OH)2(s) -> 2H2O(l) + Ca^2+(aq) we eliminated the spectator ions.

OpenStudy (anonymous):

as @iforgot said, this is the molecular equation: Ca(OH)2(s) + 2HCl(aq) --> 2H2O(l) +CaCl2 (aq) i like this version best because we don't have to assume that HCl dissociates completely (even though it usually comes very close to it). but hey, no salt dissociates 100% (and it depends on the concentrations), the "aq" designation seems to suggest that the salt is "dissolved" without forcing us to split the ion-pair apart, so i like it better.

OpenStudy (anonymous):

thank you :D

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