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OpenStudy (anonymous):
14^x+1=36? exponential equations
round to the nearest ten thousandth
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OpenStudy (anonymous):
Use Log to both sides
OpenStudy (anonymous):
log 14^x+1 = log 36
OpenStudy (anonymous):
It will be
(x+1) Log 14=Log 36
(x+1)=Log36/Log14
Can you complete ?
OpenStudy (anonymous):
after you apply the power property of logarithms right?
and im not sure
OpenStudy (anonymous):
@kaytiey :
Is that your question
\[\Large 14^{x+1}=36 \]
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
In that case ,Do as i did in the pervious steps ;
(x+1)=Log36/Log14
x =(Log36/Log14)-1= ?
OpenStudy (anonymous):
previous*
OpenStudy (anonymous):
so .3578 and round it o the nearest ten thousandth
0.358
or what?
i dont remember my places after the decimal point
OpenStudy (anonymous):
To the nearest thousandth will be 0.358
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OpenStudy (anonymous):
to the nearest ten thousandth
OpenStudy (anonymous):
*i need
OpenStudy (anonymous):
To the nearest ten thousandth ,will be 0.3580
-.
OpenStudy (anonymous):
ok ay the whole number that showed on my calculator is .357878398 so i only round the fourth place after the decimalcorrect?
OpenStudy (anonymous):
Correct :!
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OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
Yw
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