Suppose C is any curve from (0,0,0) to (1,1,1) and F(x,y,z) = (5z+4y)i + (4z+4x)j + (4y+5x)k. Compute the line integral F*dr Thanks
since the path is irrelevant, wouldnt making it a line be simple?
r = <t,t,t> r' = <1,1,1>
F(x,y,z) = (5t+4t)i + (4t+4t)j + (4t+5t)k F(r(t)) = 9t i + 8t j + 9t k F*r' = 26t
\[\int_{0}^{1}26t~dt=13\]
I don't think that is right. Does it sound right to do something like find ∇f for each i,j, and k and then combine them?
gradients do sound familiar, but fuzzy http://tutorial.math.lamar.edu/Classes/CalcIII/FundThmLineIntegrals.aspx
I just did it that with gradients and I got the same answer as you did. Thanks
YAY!! :)
http://tutorial.math.lamar.edu/Classes/CalcIII/LineIntegralsVectorFields.aspx this is what i was trying to refresh my memory with
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