Question

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Answer 1

You are to construct an open rectangular box with a square base and a volume of 48 ft^3. If material for the bottom costs $6/ft^2 and the material for the sides costs $4/ft^2 what dimensions will result in the least expensive box. What are its dimensions.

Answer 2

I have a lot of HW so I'll not answere it but you only have to use applications of differential calculus, just draw you box and use the formula for the volume...

Answer 3

i realize that.

Answer 4

i understand that v=x^2h .. thus h = 48/x^2

Answer 5

so I guess I just need to know.... do I calculate maximum cost or do I calculate the dimensions?

Answer 6

or.. is that not the right thought process?

Answer 7

you have to get the minimum of material in that way you make the box cheaper

Answer 8

so create a function for cost?

Answer 9

so yes, just the dimensions

Answer 10

I'm waiting for someone that could help me with one of my HW problems...