Solve. 10/(3x) + 4/3 = (7 + x)/2x A) x = 1/3 B) x = 17/5x C) x = 1/5 D) x = 1/6 help?? please.. I'm begging you. Medal to answer
first eliminate all fractions. what can you multiply by to do this?
@Peter14 honestly, no idea.. can you help me with this, like show me how to solve, so I can try to solve the next one on my own? it's the only thing that helps me.. thank you so much im like about to cry
\[\frac{ 10 }{ 3x }+\frac{4}{3} = \frac{7+x}{2x}\]
multiply everything by 6x 20+8x=(7+x)3x see how I did that?
@Peter14 I think so..Is that the final answer?
no, that's not the final answer. do you know how to take it from there? you distribute the 3x and then solve it as a quadratic.
one minute, switching classes...
@Peter14 like I said, I'm so unsure.. can you solve this for me so I can see how to apply it with the next problem? I'm so sorry for the inconvinience..
...
i'm back
20+8x=21x+3x^2
3x^2+13x+20=0
@Peter14 okay.. i understand that
then use the quadratic formula
@Peter14 like I said, I don't know how to do that..
@Peter14 so sorry for the trouble, I cant thank you enugh
i'll find a site to teach you that....
it's no trouble
http://www.purplemath.com/modules/quadform.htm or http://www.sosmath.com/algebra/quadraticeq/quadraformula/quadraformula.html
@Peter14 thank you!! (: what is the final answer, so I can tell if I got it right?
purplemath if you like words, sosmath if you like them to do a sample problem
@Peter14 oh, okay!! :) what's the final answer to this?
I may have made a mistake earlier in the problem, but I don't think it has real answers...
@Peter14 what? can you see again.. please??
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@Peter14 i see..
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20x+8x^2=21x+3x^2 looks like I did do something wrong
no, I did something wrong this time. (facepalm)
and last time (facepalm)
@peter14 oh..it's okay! i appreciate this so much :) do you think you can find the asnwer?
yes, I can.
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