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Mathematics
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integrate (x - x³)
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integrate x and integrate -x^3 separately
\[\int\limits (x-x^3)dx=\frac{1}{2}x^2-\frac{1}{4}x^4+C\]
Anti-differentiate.
Work backwards from differentiating. How would you get x from the first place? You would differentiate x^2. but there's no 2 at the front so you put a half at the front to cancel at the 2.
Same goes for x^3. You would originally have x^4 but there's no 4 at the front so you bring a quarter down the front to cancel it out.
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cancel out*
\[\int\limits_{}^{}x ^{n}dx=x ^{n+1}/(n+1)\]
\[\int\limits_{}^{}(x-y)dx=\int\limits_{}^{}(x)dx-\int\limits_{}^{}(y)dx\]
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