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Mathematics 15 Online
OpenStudy (anonymous):

integrate (x - x³)

OpenStudy (anonymous):

integrate x and integrate -x^3 separately

OpenStudy (anonymous):

\[\int\limits (x-x^3)dx=\frac{1}{2}x^2-\frac{1}{4}x^4+C\]

OpenStudy (anonymous):

Anti-differentiate.

OpenStudy (anonymous):

Work backwards from differentiating. How would you get x from the first place? You would differentiate x^2. but there's no 2 at the front so you put a half at the front to cancel at the 2.

OpenStudy (anonymous):

Same goes for x^3. You would originally have x^4 but there's no 4 at the front so you bring a quarter down the front to cancel it out.

OpenStudy (anonymous):

cancel out*

OpenStudy (anonymous):

\[\int\limits_{}^{}x ^{n}dx=x ^{n+1}/(n+1)\]

OpenStudy (anonymous):

\[\int\limits_{}^{}(x-y)dx=\int\limits_{}^{}(x)dx-\int\limits_{}^{}(y)dx\]

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