Question

Plank's constant help

Answer 1

Laser eye surgery is carried out by delivering highly intense bursts of energy using electromagnetic waves. A typical laser used in such surgery has a wavelength of 190 nm (ultraviolet light) and produces bursts of light that last for 1 ms. It delivers an energy of 0.5 mJ to a circular spot on the cornea with a diameter of 1 mm. (The light is well approximated by a plane wave for the short distance between the laser and the cornea.)

Estimate the maximum strength of the electric field in one of these pulses.

Answer 2

The value of wavelength given is not needed for the ans.
When the laser light travels to the cornea, it travels in form of a cylindrical envelope from the initial to the final point. The total volume of this cylinder= pi*r^2*h
The radius is given and the height will be the distance traveled by light in 1ms i.e. c* 0.001s.
Thus the energy density of this wave = 0.5 mj/ volume enclosed
Also the enegry density = \[1/2\times \epsilon \times E ^{2}\]
Equating the two eqns u ll get the max value of the electric field.

Answer 3

would you get the answer plz

Answer 4

Its a big calculation, not sure about my ans..Is it somwhere around 2.18\[\times 10^{-2}\]

Answer 5

nop

Answer 6

Wat is it?

Answer 7

10^-15 something

Answer 8

I can vouch for the method...might have some calculation errors...calculate it once, see if it matches.